Answers to to Your Questions - Page 2 |

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Here you get answers of your CBSE mathematics 1X and X questions by our experienced teachers. To ask a question click here |

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Question 16. I need CBSE maths new paper pattern. by Ashmita, class X answered on Jan 9, 2007 at 8:00 a.m. (+ 5.5 G.M.T.)
Answer 16. You can download it from here click here |

Question 17. Can i get full information about project work of 10th board exam? by sunny kejriwal, answered on Jan 10, 2007 at 9:08 p.m. I.S.T.
Answer 17. Sure, you can download Maths Lab Manual from here. click here The Project work in maths carries 5 marks and out of 5 project you have to make one project. If after going through the Lab manual if you have any doubt feel free to contact us again. |

Question 18. Find the value of p for which the points (-5,1),(1,p),(4,-2) are collinear. by Chandini class x answered on Jan 11, 2007 at 10:15 I.S.T.
Answer 18. Let (1,p) divides the join of (-5,1) and (4,-2) in ratio k:1. Using section formula 1 = (4k - 5)/(k+1) k = 2 p = (- 2k+1)/(k+1) p = - 1 |

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Question 19. Can you please tell what is Siddhacharyas formula? by ravikant class X answered on Jan 12, 2007 at 7:40 p.m. I.S.T.
Answer 19. Quadratic formula is called Siddhacharyas formula. |

Question 20. Find probability of 53 Sundays in a leap year. by Simran class x, answered on Jan 13, 2007 at 8:15 a.m.
Answer 20. Total days in a leap year is 366. (366/7) = 52 2/7. So there are 52 sundays the remaining two days can be any two consecutive days for example sunday and monday. Out of the total outcomes thus obtained 2 contain sunday.So the Probability of 53 sundays in a leap is 2/7. |

Question 21. I have not recieved the answer of my 9th class question. i had asked the question in last week.by Hitesh Kumar class IX, answered on Jan 14, 2007 at 9:00 p.m. I.S.T.
Answer 21. At this time we are answering only one question per day, so we are not able to answer all questions we receive . We are receiving more than 50 questions per day. You have asked second time so we will try to answer your question at the earliest. |

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Question 22. Sum of 3 terms of an A.P. is 3 and product is - 24. Find the three of A.P. by Aakansha class x, answered on Jan 17, 2007 at 10:00 p.m. I.S.T.
Answer 22. Let the 3 terms be a - d, a, a + d Sum = a - d + a + a + d = 3 3a = 3 a = 1 Product = (a + d)a(a - d) = - 24 (1 + d)1(1 - d) = - 24 (since a = 1) 1 - d^2 = - 24 d = +- 5 Terms of A.P. are -4, 1, 6 or 6, 1, - 4 |

Question 23. I want your suggestion for my son about maths for comming exam cbse final 2007 by Arup Kr, Das, answered on Jan 19, 2007 at 5:31 p.m. I.S.T.
Answer 23. For maths exam suggestion refer this page click here. If you have any other question write to us once again through the same form. |

Question 24. Find the sum of first hundred even positive integers divisible by 5 by Debanik Bhattacharjee answered on Jan 20, 2007 at 8:05 a.m. I.S.T. ( +5.5 G.M.T.)
Answer 24. A.P. of reqd. numbers is 10, 20, 30, 40, ......... Here first term = a = 10, common difference = d = 10 100th term = a + 99 d = 1000 Sum of 100 terms n/2(a + l) where l is last term = 100/2(10 + 1000) = 50500 |

Question 25. Sum of 3terms of A.P. is 36 and product is 1296. Find A.P? by mohammed noufal answered on Jan 21, 2007 at 9:43 p.m. I.S.T.
Answer 25. This type of question has been answered (see Q 22) |