CBSE math

CBSE maths CBSE Sample Guess Question Papers CBSE results social science hindi X X11 syllabus



Question 121. Are there geometric figures which are always similar? by Ritika. Answered on Jan 16, 2007 at 8:20 p.m.
Answer 121. Yes. Circles, equilateral triangles and all other regular polygons are always similar.
Question 122. Find the sum of all two digit numbers which when divided by 9, yield 1 as remainder, by Nishajith. Answered on Jan 20, 2008 at 8:09 pm I.S.T
Answer 122. The Numbers of this type are 10, 19, 28, 37,...,91.
                      First term = a = 10
                      common difference = d = 19 - 10
                                                      = 9
                      last term = Tn = 91
                      a + (n - 1)d = 91
                      10 +
(n - 1)9 = 91
                     
(n - 1)9 = 81
                      
n - 1 = 9
                       n = 9 + 1
                          =  10
                       Sum = S10 = n/2 (a + l)
                                       = 10/2 ( 10 + 91)
                                       = 5 (101)
                                       = 505
Question 123. Write a linear equation which passes through x = 2 and y = 3. How many such lines are possible.by Raman. Answered on Jan 21, 2007 at 10:21 pm I.S.T.
Answer 123. x + y = 5. Infinitely many lines are possible.    
Question 124. How many tangents can be drawn to a circle from a point in its interior? by Shahnaz. Answered on Jan 25, 2008 at 10:43 pm I.S.T.     
Answer 124. None. Tangents can be drawn from an exterior point or a point on the circle.
Question 125. The sum of ages of A and B  is 49 years. A said to B, " I am twice as old as you were when I was as old as you are. Find their present ages by Ravi. Answered on Jan 31, 2007 at 9:14 pm I.S.T.
Answer 125. Let age of A = x years
                    
Let age of B = y years
                     Difference of their ages = (x - y) years
                     according to first condition
                     x = 2 [ y -
(x - y) ]
                    
x = 2 ( y - x + y )
                     x = 2 ( 2y - x )
                    
x =  4y - 2x
                     3x = 4y  ..............(i)
                    
according to second condition
                     x + y = 49
                     x = 49 - y ............(ii)
                     From i and ii
                     3 (
49 - y) = 4y
                     147 - 3y = 4y
                     7y = 147
                      y = 21
                      Substituting in ii
                      x = 28
                      Age of A = 28 years
                     
Age of A = 21 years
                   

Question 126. Suppose you drop a dice in a rectangular region with sides 6 m and 4 m. A circle is of diameter 1 m is drawn inside it. What is probability that it will land inside the circle. by Neerja. Answered on Feb 7, 2008 at 10:38 p.m.
Answer 126. Area of rectangular region = 6 × 4
                                                         = 24 square metre
                     Area of circle = pie/4  square metre
                     Required probability = (pie/4)/24
                                                = pie/96
Question 127. prove that the area of triangle whose coordinates are (t,t-2),(t+23,t+2)and (t+3,t) is independent of t by Puneet Singh. Answered on Feb 10, 2007 at 11:11 pm
Answer 127. Area of triangle = 1/2 | t(t + 2 - t) + (t + 23)(t - t + 2) + (t + 3)(t - 2 - t - 2)|
                                                = 1/2 | 2t + 2t + 46 - 4t - 12|
                                                = 1/2 |34|
                                                = 17 square units
                                               So we see area of triangle does not contain t and hence is independent of t
Question 128. determine the ratio in which the line 2x+y-4=0 divides the line segment joining the points A(2,-2) and B(3,7) by Sukhmani Lamba. Answered on Feb 12, 2007 at 9:12 p.m.
Answer 128. Let the coordinates of point of intersection be (x,y) and let it divide the line segment AB in ratio
                               k:1.                      
                               So x = (2 + 3k)/(k+1)  and y = (- 2 + 7k)/(k+1)
                               Putting these values in the equation of given line we get
                              2
(2 + 3k)/(k+1)  +  (- 2 + 7k)/(k+1)  -  4 = 0
                             
(4 + 6k)/(k+1)  +  (- 2 + 7k)/(k+1)  -  4 = 0
                             
(4 + 6k - 2 + 7k)/(k+1)   =  4
                              (2 + 13k)
/(k+1)   =  4
                              
2 + 13k = 4k + 4
                              9k = 2
                              k = 2/9
                              Required ratio = 2:9
                  
           
Question 129. (x-2) and (x-1/2) are the factorsof the polynomials qx^2+5x+r prove that q=r, by Arushi Gautam. Answered on Feb 14, 2007 at 9:37 pm I.S.T.
Answer 129. Let f(x) = qx^2+5x+r
                                Since x - 2 is a factor therefore
f(2) = 0 by factor theorem
                                q(2^2) + 5(2) + r = 0
                                4q + r = - 10   ........(i)
                               
Since x - 1/2 is a factor therefore f(1/2) = 0 by factor theorem
                               
q(1/2)^2 + 5(1/2) + r = 0
                                q/4 + r = - 5/2  .....(ii)
                                     (i) - (ii)
                                 4q - q/4 = - 10 + 5/2
            (
×4)             16q - q  = - 40 + 10
                                 15 q = - 30
                                  q = - 2
                                  Substituting in (i)
                                  4(- 2) + r = - 10
                                   r = - 10 + 8
                                   r = - 2
                                   Therefore p = q = -2
        
Question 130. If 3cot A=4, check whether1-tan^2 A / 1+tan^2 A = cos^2 A - sin^2 A or not by Unnikrishnan.
Answered on Feb 16, 2007 at 7:38pm I.S.T.
Answer 130.3cot A=4
                             or cot A = 4/3 = adjacent side/opposite side
                                  Let
adjacent side = 4k and opposite side = 3k
                                 Hypotenuse = 5k  
                                 L.H.S. =   
1-tan^2 A / 1+tan^2 A
                                             =     [1 - (3/4)^2]/
  [1 + (3/4)^2]
                                             =     [ 1 - 9/16]/
[ 1 + 9/16]
                                            
=     [7/16]/[25/16]
                                             =     7/16  
×   16/25 
                                             =     7/25
                                 R.H.S. =    
cos^2 A - sin^2 A
                                             =     [4/5]^2 -
[3/5]^2
                                            
=     16/25 - 9/25
                                            =       7/25
                                  Therefore L.H.S. = R.H.S.
                           



Question 131.A die is thrown once. Find probability of getting a composite or prime number by Parkash. Answered on Feb 17, 2008 at 8:19 pm I.S.T.
Answer 131. Favorable outcomes = 5  (2, 3, 4, 5, 6), Total outcomes = 6 (1, 2, 3, 4, 5, 6)
                                 Required Probability =
Favorable outcomes/Total outcomes
                                                                      =  5/6
                                  Note - 1 is neither composite nor Prime
Question 132. Sir, by when will the Maths (class X ) Mock test be available ? What about the answers? by Sukhman deep. Answered on Feb 23, 2008 at 1:08 a.m. I.S.T.                              
Answer 132. We plan to add  two Mathematics class X Mock tests with answers. One has been already added today. The answers will be added in a few days. The second mock test we plan to add in March before  Mathematics board exam.  It is available here
Question 133.Explain why 7×11×13+13 is composite numbers by Surbhi Agarwal. Answered on Feb 25, 2007 at 11:39 pm I.S.T.
Answer 133. 7×11×13+13
                              = 13(7
×11 + 1)
                              =  13(78)
                              Now this number has more than two factors.
                              Therefore it is a composite number.
                               
Question 134. Write the least even prime number. What are Prime numbers? by Vishnoo Prashanth. Answered on Feb 26, 2008 at 9:50 pm I.S.T.
Answer 134.The numbers which have exactly two factors are called prime numbers. These factors are 1 and the number itself.  Least and the only even prime number is 2.
Question 135.Is  [3^(1/2).x^2 + 5x -11]/[3.x^2 + 9]  a rational expression? Why? by  Surbhi Agarwal. Answered on  Feb 28, 2008 at  7:12 pm I.S.T.
Answer 135. Yes. Because it is of the form polynomial/ polynomial and denominator not equal to zero.

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